Description
A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = < x1, x2, ..., xm > another sequence Z = < z1, z2, ..., zk > is a subsequence of X if there exists a strictly increasing sequence < i1, i2, ..., ik > of indices of X such that for all j = 1,2,…,k, xij = zj. For example, Z = < a, b, f, c > is a subsequence of X = < a, b, c, f, b, c > with index sequence < 1, 2, 4, 6 >. Given two sequences X and Y the problem is to find the length of the maximum-length common subsequence of X and Y.
Input
The program input is from the std input. Each data set in the input contains two strings representing the given sequences. The sequences are separated by any number of white spaces. The input data are correct.
Output
For each set of data the program prints on the standard output the length of the maximum-length common subsequence from the beginning of a separate line.
Sample Input
abcfbc abfcab
programming contest
abcd mnp
Sample Output
4
2
0
Code
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 | #include <stdio.h> #include <string.h> const int MAX = 1000 char sz1[MAX], sz2[MAX]; int aMaxLen[MAX][MAX]; int main () { while (scanf ("%s%s", sz1 + 1, sz2 + 1) != EOF) { int len1, len2; len1 = strlen (sz1 + 1); len2 = strlen (sz2 + 1); int i, j; for (i = 0; i < len1; i++) aMaxLen[i][0] = 0; for (j = 0; j < len1; j++) aMaxLen[0][j] = 0; for (i = 1; i <= len1; i++) for (j = 1; j <= len2; j++) if (sz1[i] == sz2[j]) aMaxLen[i][j] = 1 + aMaxLen[i - 1][j - 1]; else aMaxLen[i][j] = aMaxLen[i - 1][j] > aMaxLen[i][j - 1] ? aMaxLen[i - 1][j] : aMaxLen[i][j - 1]; printf ("%d\n", aMaxLen[len1][len2]); } return 0; } |
你好!除了代码,此处没有多少原创之物,皆为本人搜集、整理、总结之记录与心得,欢迎转载分享!转载时请尽量注明出处,将不胜感激。祝你健康、快乐!
Be the first to comment on this entry.